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Question

Question: What is the integral of \( 2x{e^x}? \)...

What is the integral of 2xex?2x{e^x}?

Explanation

Solution

Hint : As we can see that we have to solve the given integral. We can solve this integral by using the formula of integration by parts and doing some calculations we will get the required answer. We will be using the formula which is udv=uvvdu\int {udv = uv - \int {vdu} } .

Complete step-by-step answer :
Here we have to find the integral of 2xex2x{e^x} .
So we can write it as 2xexdx\int {2x{e^x}dx} . We have to solve this.
We can see that there is a constant value in the expression i.e. 22 . Since it is an integral value we can take it outside the integral sign and thus the equation can be re-written as 2xexdx2\int {x{e^x}dx} .
Let us assume that I=xexdxI = \int {x{e^x}dx} . So we can write 2xexdx2\int {x{e^x}dx} as 2I2I .
Now by applying the formula of integral by parts and by comparing we have uxu \to x , so we say du=dxdu = dx .
And we have dv=exdxdv = {e^x}dx , therefore v=exv = {e^x} .
By substituting the values in the formula we can write
xexdx=xexexdx\int {x{e^x}dx = x{e^x} - \int {{e^x}dx} } .
We can cancel out the common terms, thus it gives exdx=ex\int {{e^x}dx = {e^x}} . On further integrating we can write xexdx=xexex\int {x{e^x}dx = x{e^x} - {e^x}} .
From the above we have I=xexdxI = \int {x{e^x}dx} , so we can rewrite it as I=xexexI = x{e^x} - {e^x} .
Therefore we have 2xexdx2\int {x{e^x}dx} as 2I2I , so 2xexdx2\int {x{e^x}dx} =2(xexex)+C= 2(x{e^x} - {e^x}) + C .
Hence the required integral value of 2xexdx2\int {x{e^x}dx} is 2(xexex)+C2(x{e^x} - {e^x}) + C .
So, the correct answer is “ 2(xexex)+C2(x{e^x} - {e^x}) + C ”.

Note : We should note that the integral of ex{e^x} with respect to xx is ex{e^x} . Before solving this kind of question we should be fully aware of the integration and their formulas. We should avoid the calculation mistake. All the basic integration and derivative formulas should be memorized to solve these types of questions.