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Question: What is the impulse of a body is equal to: (A) Rate of change in momentum (B) Change in momentum...

What is the impulse of a body is equal to:
(A) Rate of change in momentum
(B) Change in momentum
(C) The product of the force applied on it and the time of application of force
(D) Both (B) and (C)

Explanation

Solution

We need to derive the equation of force from Newton’s second law of motion. Then on relating this to the definition of impulse we will get the correct answer from the options given in the question.

Formula Used: The following formulas are used to solve this question.
F=dpdtF = \dfrac{{dp}}{{dt}} where pp is the linear momentum and tt is the change in time.
J=FtJ = \int {F \cdot t} where JJ is the impulse, resultant force is FF and time is tt.
J=t1t2dpdtdtJ = \int\limits_{{t_1}}^{{t_2}} {\dfrac{{dp}}{{dt}}} dt where impulse is integral over the closed interval t2{t_2} to t1{t_1} where t2{t_2} is the final time and t1{t_1} is the initial time.

Complete step by step answer
Impulse (symbolized by JJ or Imp) is the integral of a force, FF, over the time interval, tt, for which it acts.
Since force is a vector quantity, impulse is also a vector quantity.
Impulse applied to an object produces an equivalent vector change in its linear momentum, also in the same direction. The SI unit of impulse is the Newton second ( NsN \cdot s ).
The impulse ( JJ ) is the integral of the resultant force (F) with respect to time ( tt ):
J=FtJ = \int {F \cdot t} where JJ is the impulse, resultant force is FF and time is tt.
Thus, impulse of a body is equal to the product of the force applied on it and the time of application of force. Thus, option C is true.
From Newton’s second law, force FF is the rate of change of momentum.
F=dpdtF = \dfrac{{dp}}{{dt}} where pp is the linear momentum and tt is the change in time.
According to the impulse-momentum theorem,
J=t1t2dpdtdtJ = \int\limits_{{t_1}}^{{t_2}} {\dfrac{{dp}}{{dt}}} dt where impulse is integral over the closed interval t2{t_2} to t1{t_1} where t2{t_2} is the final time and t1{t_1} is the initial time.
J=p1p2dpJ = \int\limits_{{p_1}}^{{p_2}} {dp} where impulse is integral over the closed interval p2{p_2} to p1{p_1} where p2{p_2} is the final momentum and p1{p_1} is the initial momentum.
=p2p1=Δp= {p_2} - {p_1} = \Delta p is the change in linear momentum in a time interval.
Thus the impulse of a body is equal to change in linear momentum in a time interval. Thus Option B is true.

\therefore The correct answer is Option D.

Note
In a collision, objects experience an impulse; the impulse causes and is equal to the change in momentum. The result of the force acting for the given amount of time is that the object's mass either speeds up or slows down (or changes direction).