Question
Question: What is the impedance of the circuit shown in the figure given below? 2+R2.
Complete step by step answer:
Let us first understand the impedance formula. Impedance is denoted by Z and resistance of an inductor is given by XL=IV since, voltage across the inductor is given in figure as Vinductor=120V . And since, current is flowing in the circuit which is given by, I=3A .
Since, both resistor and inductor are connected in series, and we also know in series circuits current flows equally in all components of circuit which means the same current I=3A will flow in both resistor and inductor. Now, the value of resistance in inductor is given by:
XL=IV
⇒XL=3120
⇒XL=40ohm→(i)
Now, we will find the magnitude of resistance across the resistor.
From given figure, voltage across the resistor is 90V
R=IV
⇒R=390
⇒R=30ohm→(ii)
From equations (i)and(ii) we get the value of impedance as
Z=(XL)2+R2
Putting the values from (i)and(ii) ,
Z=1600+900
⇒Z=2500
∴Z=50ohm
So, the net resistance which is known as impedance is Z=50ohm.
Hence, the correct option is B.
Note: Remember, in electrical circuit when inductor and resistor are connected in series then they are in phase difference of 90∘ where current lags behind the voltage by 90∘ and so their net impedance term of cosϕ became zero since cos90∘=0 hence, impedance is simply the root of sum of squares of inductance and resistance.