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Question: What is the impedance of the circuit shown in the figure given below? ![](https://www.vedantu.com/...

What is the impedance of the circuit shown in the figure given below?

A. 100ohm100\,ohm
B. 50ohm50\,ohm
C. 30ohm30\,ohm
D. 40ohm40\,ohm

Explanation

Solution

Impedance is the net resistance of ac circuits when inductors, capacitors and resistors are used in a circuit. We will find the value of resistance of resistor and inductor separately and then using the formula of finding impedance which is given as Z=(XL)2+R2Z = \sqrt {{{({X_L})}^2} + {R^2}} .

Complete step by step answer:
Let us first understand the impedance formula. Impedance is denoted by ZZ and resistance of an inductor is given by XL=VI{X_L} = \dfrac{V}{I} since, voltage across the inductor is given in figure as Vinductor=120V{V_{inductor}} = 120V . And since, current is flowing in the circuit which is given by, I=3AI = 3A .

Since, both resistor and inductor are connected in series, and we also know in series circuits current flows equally in all components of circuit which means the same current I=3AI = 3A will flow in both resistor and inductor. Now, the value of resistance in inductor is given by:
XL=VI{X_L} = \dfrac{V}{I}
XL=1203\Rightarrow {X_L} = \dfrac{{120}}{3}
XL=40ohm(i)\Rightarrow {X_L} = 40\,ohm \to (i)
Now, we will find the magnitude of resistance across the resistor.

From given figure, voltage across the resistor is 90V90V
R=VIR = \dfrac{V}{I}
R=903\Rightarrow R = \dfrac{{90}}{3}
R=30ohm(ii)\Rightarrow R = 30\,ohm \to (ii)
From equations (i)and(ii)(i)and(ii) we get the value of impedance as
Z=(XL)2+R2Z = \sqrt {{{({X_L})}^2} + {R^2}}
Putting the values from (i)and(ii)(i)and(ii) ,
Z=1600+900Z = \sqrt {1600 + 900}
Z=2500\Rightarrow Z = \sqrt {2500}
Z=50ohm\therefore Z = 50\,ohm
So, the net resistance which is known as impedance is Z=50ohmZ = 50\,ohm.

Hence, the correct option is B.

Note: Remember, in electrical circuit when inductor and resistor are connected in series then they are in phase difference of 90{90^ \circ } where current lags behind the voltage by 90{90^ \circ } and so their net impedance term of cosϕ\cos \phi became zero since cos90=0\cos {90^ \circ } = 0 hence, impedance is simply the root of sum of squares of inductance and resistance.