Question

What is the hybridization and geometry of the compound $XeOF_4$ ?

• A. $sp^3\,d^2$ and octahedral
• B. $sp^3\,d$ and square pyramidal
• C. $sp^3\,d$ and trigonal bipyramidal
• D. $sp^3\,d^2$ and square pyramidal

Answer 1

Answer: (D)

$sp^3\,d^2$ and square pyramidal

Answer 2

Number of hybrid orbitals $(X)$
$=\frac{1}{2}(V.E. +M.A. -c+a)$
For, $XeOF_{4}$
$V.E. =8; M.A.$ (monovalent atoms) $= 4$
$(X)=\frac{1}{2}(8+4)\Rightarrow 6$
i.e., $sp^{3} d^{2}$ hybridisation