Question
Question: What is the hybridisation of \[SO_4^{2 - }\] ion?...
What is the hybridisation of SO42− ion?
Solution
To know the characteristic geometrical shapes of polyatomic molecules the concept of hybridisation was introduced. The atomic orbitals combine to form a new set of equivalent orbitals known as hybrid orbitals. Hybridisation is a process of intermixing of the orbitals of slightly different energies so that it redistributes the energies resulting in the formation of new orbitals of equivalent energies and shape.
Example- one 2s and three 2p orbitals of carbon hybridise to form four new sp3 hybrid orbitals.
Complete answer:
Sulphate(SO42−) is one of the most widely naturally available chemical compounds.
Sulphate is basically a chemical compound that is composed of sulphur and oxygen atoms. Sulphate forms salts with a variety of elements .
The number of sigma bond and lone pair electrons provides details regarding ion hybridisation.
sp hybridisation- Number of sigma bond and lone pair of electrons is 2.
sp2 hybridisation- Number of sigma bonds and lone pair of electrons is 3.
sp3 hybridisation- Number of sigma bonds and lone pair of electrons is 4.
According to VSEPR theory the SO42− ion has tetrahedral molecular geometry. The SO42− ion has four oxygen atoms arranged tetrahedrally around the sulphur atom. So, there are a total of four S−O sigma bonds and all four bonds are of equal lengths. Hence SO42− ion has sp3 hybridisation. The extra two electrons of sulphur form two double bonds to oxygen then they move over to their oxygen forming a net negative charge on each of the four oxygen atoms.
Note:
In each sp3 hybrid orbital there will be 25% s-character and 75% p-character. The angle between the sp3 hybrid orbital is 109.50. The other examples for sp3 hybridisation is NH3, H2O,CH4,C2H6 molecules etc. there are hybridisation involving d orbitals. They are dsp2,sp3d,sp3d2 and d2sp3 hybridisation. These are the hybridisations for higher molecules.