Question

What is the hit and trial method?

Answer 1

This strategy is also known as the inspection method or the trial and error approach. This method adjusts the coefficient before the equations or symbols of the reactants and products so that the total number of atoms of each element is equal on both sides.

Complete answer:
Let us see about chemical equations. Because no matter is destroyed or generated during a chemical reaction, i.e. energy is never destroyed or created, the product side must have the same amount of elements as the reactant side. It is for this reason that chemical reactions must be balanced. In both the reactant and product sides, balancing a chemical equation is accomplished by placing a suitable integer before the components or compounds.
Chemical equations can be balanced in two ways:
1.Hit and Trial Method
2.Partial equation method.
Let us talk about Hit and Trial Method. Chemical equations are balanced by adding stoichiometric coefficients to the reactants and products. It's significant because the laws of conservation of mass and constant proportions must be enforced by a chemical equation in which the same number of atoms of the reactant and product sides of the equation must remain constant.
Experiments are carried out utilising the least whole number coefficient to balance chemical equations in the hit and trial method of balancing chemical equations. As a result, it's known as the hit and trial method.
Count the number of times an element appears on both sides.
To begin, an element with the lowest frequency of occurrence is balanced.
Because two or more elements have the same frequency, metallic elements are matched first.

Note:
Let us see how we can balance this equation:
$2{H_2} + 3{O_2} \to 2{H_2}O.$
Step 1: Equalize the number of oxygen atoms on both sides of the equation. There are $6$ oxygen atoms on the reactant side. As a result, we'll multiply the product side by three to achieve balance.
Step 2: We'll now balance the number of hydrogen atoms in the system. We'll multiply ${H_2}$ by $3$ because there are $12$ hydrogen atoms on the product side.
The result of a balanced reaction is
$6{H_2} + 3{O_2} \to 6{H_2}O$