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Chemistry Question on GROUP 1 ELEMENTS

What is the heat of solution of sodium chloride from following data? Hydration energy of Na+=−389.4 kJ mol−1Na^+ = - 389.4\, kJ\, mol^{-1} Hydration energy of Cl−=−382.3 kJ mol−1Cl^- = - 382.3\, kJ\, mol^{-1} Lattice energy of NaCl=−776 kJ mol−1NaCl = - 776 \,kJ \,mol^{-1}

A

+8.6 kJ mol−1+ 8.6\, kJ\, mol^{-1}

B

+4.3 kJ mol−1+ 4.3\, kJ\, mol^{-1}

C

−4.3 kJ mol−1- 4.3\, kJ\, mol^{-1}

D

−8.6 kJ mol−1- 8.6\, kJ\, mol^{-1}

Answer

+4.3 kJ mol−1+ 4.3\, kJ\, mol^{-1}

Explanation

Solution

Hydration energy of NaCl=−389.4−382.3NaCl = - 389.4 - 382.3 =−771.7 kJ mol−1= -771.7\, kJ \,mol^{-1} ?Hsol.=?H_{sol}. = Hydration energy - Lattice energy =−771.7−(−776)=+4.3 kJ mol−1= - 771.7 - (-776) = + 4.3 \,kJ \,mol^{-1}