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Question: What is the freezing point for the solution of 2,000 grams of water (essentially 2L) and 684 grams o...

What is the freezing point for the solution of 2,000 grams of water (essentially 2L) and 684 grams of sucrose (molecular mass = 342 gram per mole) dissolved in it?
a.) 1.860C - {1.86^0}C
b.) 6.780C - {6.78^0}C
c.) 3.720C - {3.72^0}C
d.) 510C - {51^0}C

Explanation

Solution

Hint: In order to solve this question, we will use some concept like when any solute is dissolved or put in a solvent the overall freezing point of the solvent decreases. As in the above question we will find the new freezing point as we know the freezing point of water is 0 degree Celsius. We will begin with calculating the moles of solute and the proceed accordingly

Complete step by step solution: Formula used- the freezing point depression
ΔT=Kfm\Delta T = {K_f}m
Where ΔT\Delta T is freezing point depression
Kf{K_f} is the molal freezing point depression constant
mm is the molality of the solute.
Given
Mass of sucrose = 684g
Molecular mass of sucrose = 342g
Mass of water = 2000g = 2kg
Number of moles of sucrose = massmolecularmass=684342=2moles\dfrac{{mass}}{{molecular\,mass}} = \dfrac{{684}}{{342}} = 2\,moles
As we know that the molality of a solution is given as
m=number of molesvolume of water in kgm = \dfrac{{{\text{number of moles}}}}{{{\text{volume of water in kg}}}}
Using the above formula to find the molality of sucrose solution
m=number of molesvolume of water in kg m=22=1  m = \dfrac{{{\text{number of moles}}}}{{{\text{volume of water in kg}}}} \\\ m = \dfrac{2}{2} = 1 \\\
Now, using the formula of depression in freezing point to determine the change in the freezing point after addition of solute
ΔT=Kfm ΔT=1.86×1 ΔT=1.860C  \Delta T = {K_f}m \\\ \Delta T = 1.86 \times 1 \\\ \Delta T = {1.86^0}C \\\
As we know the freezing point of the water is 0 degree Celsius.
Therefore the freezing point of the solution will be
=01.86 =1.860C  = 0 - 1.86 \\\ = - {1.86^0}C \\\

Hence, the correct option is A.

Note: As we know that the freezing point is a phenomena that tells us about why addition of solute to a solvent changes the freezing point of the solution. Once a material begins freezing, due to the decreases in temperature, the molecules slow down and the intermolecular forces start taking over. Instead the molecules are arranged in a pattern, and thus become solid. For example when water is cooled to the freezing point, the molecules become slower and hydrogen bonds tend to "stick" more and gradually create a solid.