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Question: What is the formula of tetrakis(pyridine) platinum(ii) tetraphenyl borate(iii)?...

What is the formula of tetrakis(pyridine) platinum(ii) tetraphenyl borate(iii)?

Explanation

Solution

The complex is a coordination compound. The oxidation states of the metal are given in brackets. Ligands are ions or molecules that are directly attached to the metal atom. Here two ligands are present, and two metal atoms are present. Formula can be found by adding the charge of the ligands and metal. Here, pyridine is a neutral ligand and phenyl is an anionic ligand.

Complete step by step answer:
The nomenclature of coordination contains a set of rules some of the major ones are,
A. The cation or the positive ion is named first in both positively and negatively charged compounds.
B. The ligands are named first before the central metal atom. The ligands are named according to alphabetical order.
C. The anionic ligands terminate as O - O the neutral and cationic ligands remain the same except aqua for water, ammine for ammonia, carbonyl for CO{{CO}} etc.
D. The number of ligands is indicated by prefixes di, tri, tetra etc. When the ligands have a numerical prefix or polydentate ligand or a Latin name, bis, tris, tetrakis is used.
E. Oxidation state of the central metal atom is written in roman numerals in parenthesis.
F. If the complex is cation the metal is named the same and if the ion is negative, metal ends with suffix -ate.
Here in the above question, two metal atoms exist so two coordination spheres are present. Ligand pyridine is
represented by the notation py{{ - py}} and Ligand phenyl is represented by the notation (Ph)\left( {{{ - Ph}}} \right).The ligand pyridine is a
a neutral ligand and phenyl is an anionic ligand with charge 1^{{ - }}{{1}}. The total charge of the given compound is is zero
therefore, Thus the formula of the compound is tetrakis(pyridine)platinum (II)tetraphenylborate (III)
is [Pt(py)4][B(Ph)4]2\left[ {{{Pt}}{{\left( {{{py}}} \right)}_{{4}}}} \right]{\left[ {{{B}}{{\left( {{{Ph}}} \right)}_{{4}}}} \right]_{{2}}}.
The answer is [Pt(py)4][B(Ph)4]2\left[ {{{Pt}}{{\left( {{{py}}} \right)}_{{4}}}} \right]{\left[ {{{B}}{{\left( {{{Ph}}} \right)}_{{4}}}} \right]_{{2}}}.

Note: Ligands are ions or molecules that are bound to the central metal atom. Based on the number of donor atoms ligands can be monodentate, bidentate, polydentate. Denticity of a ligand is the number of ligating groups with which ligand is bound.
The central atom together with the ligand enclosed in a square bracket is called the coordination sphere. The special arrangement with which ligands are bound to the central metal atom is coordination polyhedral.