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Question

Question: What is the fifth term of the sequence \[1, - 4,16, - 64\]?...

What is the fifth term of the sequence 1,4,16,641, - 4,16, - 64?

Explanation

Solution

We will first find the type of progression and then calculate its nthterm{n^{th}}term to solve this problem then we will substitute n=5 to get the required answer.
We will know about the arithmetic progression and also about the geometric progression and ways to verify whether a given sequence is an Arithmetic progression or a Geometric progression.

Complete step by step answer:
In mathematics and mainly in sequences and progressions concepts, there are mainly two types of progressions.
Those are Arithmetic Progression (AP) and Geometric progression (GP).
If a term is continuously added to its previous term, then that sequence is called an AP.
Example of an AP is 4,7,10,13,.....4,7,10,13,.....
Here, 3 is getting added to its previous term continuously and we are getting a new term.
If a term is continuously multiplied to its previous term, then that is a GP.
Example of a GP is 1,12,14,18,......1,\dfrac{1}{2},\dfrac{1}{4},\dfrac{1}{8},......
Here, 12\dfrac{1}{2} is getting multiplied to its previous term continuously and we are getting a new term.
Consider a sequence a,b,ca,b,c
This sequence is
(1) Arithmetic Progression if there exist a common difference i.e., if ba=cb=d(constant)b - a = c - b = d({\text{constant)}}
(2) Geometric Progression if there exist a common ratio i.e., if ba=cb=r(constant)\dfrac{b}{a} = \dfrac{c}{b} = r({\text{constant)}}
So, now in the given sequence, 1,4,16,641, - 4,16, - 64, there is no constant common difference, so this sequence is not an AP.
And 41=164=6416=4(constant)\dfrac{{ - 4}}{1} = \dfrac{{16}}{{ - 4}} = \dfrac{{ - 64}}{{16}} = - 4({\text{constant)}}
So, common ratio r=4r = - 4
So, it is a GP.
Generally, a GP is written as a,ar,ar2,ar3,.....a,ar,a{r^2},a{r^3},.....
And nth{n^{th}} term is given by an=arn1{a_n} = a{r^{n - 1}}
So, here, the fifth term is a5=ar51=1(4)4{a_5} = a{r^{5 - 1}} = 1{( - 4)^4}
a5=256\Rightarrow {a_5} = 256
So, the fifth term is 256.

Note:
The first term of an arithmetic progression or a geometric progression can be a negative number also. But the first term of a GP should be a non-zero value. And the common difference and common ratio can be a negative or positive or a fractional value too. (Common ratio should not be a zero)
If the terms a,b,ca,b,c are in AP, then b=a+c2b = \dfrac{{a + c}}{2}
If the terms a,b,ca,b,c are in GP, then b=acb = \sqrt {ac} .