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Question: What is the exact value of \[{\tan ^2}45 + {\sec ^2}30\]?...

What is the exact value of tan245+sec230{\tan ^2}45 + {\sec ^2}30?

Explanation

Solution

Here in this question, we have to find the exact value of a given trigonometric function. For this first, we have to know the table of standard degree values of trigonometric ratios and by this table we can take the value of tan245{\tan ^2}45 and sec230{\sec ^2}30 then by its square value and further simplify by using a basic arithmetic operations we get the required solution.

Complete step by step solution:
A function of an angle expressed as the ratio of two of the sides of a right triangle that contains that angle; the sine, cosine, tangent, cotangent, secant, or cosecant known as trigonometric function Also called circular function.
Consider the given question:
tan245+sec230{\tan ^2}45 + {\sec ^2}30 ------ (2)
As we know, from the standard angles table of trigonometric ratios the value of tan45=1\tan {45^ \circ } = 1 and sec30=23\sec {30^ \circ } = \dfrac{2}{{\sqrt 3 }}, then
Equation (1) becomes
(1)2+(23)2\Rightarrow \,\,\,{\left( 1 \right)^2} + {\left( {\dfrac{2}{{\sqrt 3 }}} \right)^2}
By the quotient rule of exponent (ab)2=a2b2{\left( {\dfrac{a}{b}} \right)^2} = \dfrac{{{a^2}}}{{{b^2}}}, then we have
(1)2+22(3)2\Rightarrow \,\,\,{\left( 1 \right)^2} + \dfrac{{{2^2}}}{{{{\left( {\sqrt 3 } \right)}^2}}}
1+43\Rightarrow \,\,\,1 + \dfrac{4}{3}
Take 3 as LCM
3+43\Rightarrow \,\,\,\dfrac{{3 + 4}}{3}
73\Rightarrow \,\,\,\dfrac{7}{3}
On simplification, we get
2.333333\therefore \,\,\,\,2.333333
Hence, the exact value of tan245+sec230{\tan ^2}45 + {\sec ^2}30 is 2.3333332.333333.

Note:
When solving the trigonometry-based questions, we have to know the definitions and table of standard angles of all six trigonometric ratios. Remember, the table of value of standard angles 0{0^ \circ }, 30{30^ \circ }, 45{45^ \circ }, 60{60^ \circ } and 90{90^ \circ } of all six trigonometric ratios and should know the identities, double angle, half angle, sum identity and difference identity of trigonometric ratios it makes the solution more easier.