Question

What is the equivalent weight of $SnCl _{2}$ in the following reaction, $SnCl _{2}+C l_{2} \rightarrow S n C l_{4} ?$

• A. 95
• B. 45
• C. 60
• D. 30

Answer 1

Answer: (A)

95

Answer 2

Equivalent weight of $S n C l_{2}=\frac{\text { mol.wt. }}{2}=\frac{190}{2}=95$