Question: What is the equivalent mass of $IO_{4}^{-}$ when it is converted into $I_{2}$ in acid medium....

Question

What is the equivalent mass of $IO_{4}^{-}$ when it is converted into $I_{2}$ in acid medium.

Answer 1

Equivalent mass

$= \frac{\text{Molecular weight}}{\text{Change in oxidation number per mole}}$

Suppose molecular weight is $M$

Oxidation number of $I_{2}$ in $IO_{4}^{-}$ in

Acidic medium i.e., $I \times ( - 8) + 1e^{-} = + 7$

So eq. wt. $= M/7$ .

Question: What is the equivalent mass of \(IO_{4}^{-}\) when it is converted into \(I_{2}\) in acid medium....