Question
Question: What is the equation of the ellipse with foci \(( \pm 2,0)\) and eccentricity \(\frac{1}{2}\)...
What is the equation of the ellipse with foci (±2,0) and eccentricity 21
A
3x2+4y2=48
B
4x2+3y2=48
C
3x2+4y2=0
D
4x2+3y2=0
Answer
3x2+4y2=48
Explanation
Solution
Here ae=±2,∵e=21,∴a=±4
Form b2=a2(1−e2) ⇒b2=16(1−41)⇒ b2=12
Hence, the equation of ellipse is 16x2+12y2=1
or 3x2+4y2=48