Question

What is the equation for this reaction: Barium Nitrate + Sodium Carbonate?

Answer 1

Hint : This given reaction is a metathesis reaction, thus the reactants will exchange their partners namely nitrate and carbonate. Thus barium carbonate will be formed which will be insoluble in an aqueous solution.

Complete Step By Step Answer:
The given reaction is a chemical reaction, so the reactants will react to give products. Let us first list the reactants below,
Barium Nitrate: $Ba{{\left( N{{O}_{3}} \right)}_{2}}$
Sodium Carbonate: $N{{a}_{2}}C{{O}_{3}}$
The given reaction is a metathesis reaction, thus the partners of the reactants will get exchanged. Thus, Barium Nitrate becomes Barium Carbonate and Sodium Carbonate becomes Sodium Nitrate.
The reactants will react to give the following products,
Barium Carbonate: $BaC{{O}_{3}}$
Sodium Nitrate: $NaN{{O}_{3}}$
Let us see the ionic reaction occurring inside the solution, Barium will be separated and will become positively charged and will be combined with Carbonate which gets separated from Sodium Carbonate and will be negatively charged.
$B{{a}^{2+}}+C{{O}_{3}}^{2-}\to BaC{{O}_{3}}$ (s)
Here, the Barium Carbonate will be solid as it is not much soluble in an aqueous solution.
The solubility of a compound is given by its ${{K}_{sp}}$ value, the higher the ${{K}_{sp}}$ value, the higher the solubility in an aqueous solution. The ${{K}_{sp}}$ is the solubility product constant which is an equilibrium constant that shows the solubility of a solid substance in an aqueous solution.
Now, the ionic reaction of Sodium and Nitrate,
$2N{{a}^{+}}+2N{{O}_{3}}^{-}\to N{{a}_{2}}N{{O}_{3}}$
After combining these reactions and getting the final reaction, we get
$Ba{{\left( N{{O}_{3}} \right)}_{2}}\left( aq \right)+N{{a}_{2}}C{{O}_{3}}\left( aq \right)\to BaC{{O}_{3}}\left( s \right)\downarrow +2NaN{{O}_{3}}\left( aq \right)$
Thus the equation for the reaction of Barium Nitrate and Sodium Carbonate is given above.

Note :
This chemical reaction is a metathesis reaction, so the reactants will exchange their partner and give the products accordingly. It is also important to note that the ${{K}_{sp}}$ value of Barium Carbonate is not enough that it can dissolve in the aqueous solution.