Question

What is the equation for the equilibrium constant $({{K}_{c}})$ for the following reaction? $\frac{1}{2}A(g)+\frac{1}{3}B(g)\frac{2}{3}C(g)$

• A. ${{K}_{c}}=\frac{{{[A]}^{1/2}}{{[B]}^{1/3}}}{{{[C]}^{3/2}}}$
• B. ${{K}_{c}}=\frac{{{[C]}^{3/2}}}{{{[A]}^{2}}{{[B]}^{3}}}$
• C. ${{K}_{c}}=\frac{{{[C]}^{2/3}}}{{{[A]}^{1/2}}{{[B]}^{1/3}}}$
• D. ${{K}_{c}}=\frac{{{[C]}^{2/3}}}{{{[A]}^{1/2}}+{{[B]}^{1/3}}}$

Answer 1

Answer: (C)

${{K}_{c}}=\frac{{{[C]}^{2/3}}}{{{[A]}^{1/2}}{{[B]}^{1/3}}}$

Answer 2

$\frac{1}{2}A(g)+\frac{1}{3}B(g)\frac{2}{3}C(g)$ Equilibrium constant, ${{K}_{c}}=\frac{\text{Rate}\,\,\text{product}}{\text{Rate}\,\,\text{of}\,\,\text{reactant}}$ ${{K}_{c}}=\frac{{{[C]}^{2/3}}}{{{[A]}^{1/2}}{{[B]}^{1/3}}}$