Question
Question: What is the equation for a line that intersects the origin and is perpendicular to 2x – 4y = 13? (...
What is the equation for a line that intersects the origin and is perpendicular to 2x – 4y = 13?
(a) y = -2
(b) y = 2x
(c) y = -2x
(d) y=21x
(e) y=21x−413
Solution
Hint: Rearrange the given equation similar to slope – intercept form of a line, y = mx + c. Find the value of m from it. The slope of line perpendicular is negative reciprocal of m. Substitute this m and point of origin (0, 0), get value c. Then find the required equation.
Complete step by step solution:
We have been given the equation of the line as,
⇒2x−4y=13
Now let us rearrange the above expression as,
⇒4y=2x−13, divide the entire expression by 4.
44y=42x−13⇒y=2x−413 - (1)
We know that the slope – intercept form of the line is of the form,
y = mx + c – (2)
Now let us compare both equation (1) and (2).
Thus we can make out that slope = m = 21.
This line intersects the origin and it is said that it is perpendicular.
Thus the slope of the line perpendicular to this line will be the negative reciprocal i.e. m = m−1, put value of m in m−1.
Thus, m−1=21−1=−2
∴ Slope of line perpendicular to this line will be -2.
Now let us put this value of slope in equation (2), we get,
y = -2x + c – (3)
It is said that the equation intersects or passes through the origin.
Hence let us substitute (x, y) = (0, 0) in equation (3).
Thus we get, 0=−2×0+c⇒c=0
Let us put c = 0 in equation (3).