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Question: What is the enthalpy change for the given reaction, if enthalpies of formation of \(Al_{2}O_{3}\) an...

What is the enthalpy change for the given reaction, if enthalpies of formation of Al2O3Al_{2}O_{3} and Fe2O3Fe_{2}O_{3} are −1670kJmol−1- 1670kJmol^{- 1} and −834kJmol−1- 834kJmol^{- 1} respectively?

Fe2O3+2Al→Al2O3+2FeFe_{2}O_{3} + 2Al \rightarrow Al_{2}O_{3} + 2Fe

A

−836kJmol−1- 836kJmol^{- 1}

B

+836kJmol−1+ 836kJmol^{- 1}

C

−424kJmol−1- 424kJmol^{- 1}

D

+424kJmol−1+ 424kJmol^{- 1}

Answer

−836kJmol−1- 836kJmol^{- 1}

Explanation

Solution

: ΔH=∑ΔHP−∑ΔHR\Delta H = \sum\Delta H_{P} - \sum\Delta H_{R}

=−1670−(−834)=−836kJmol−1= - 1670 - ( - 834) = - 836kJmol^{- 1}