Question

What is the energy released in the fission reaction

${ } _ { 92 } ^ { 236 } \mathrm { U } \rightarrow { } _ { 46 } ^ { 117 } \mathrm { X } + { } _ { 46 } ^ { 117 } \mathrm { Y } + 2 { } _ { 0 } ^ { 1 } \mathrm { n }$

given that the binding energy per nucleon of X and Y is 8.5 MeV and that of ${}_{92}^{236}U$ is 7.6 MeV?

• A. 20 MeV
• B. 180 MeV
• C. 200 MeV
• D. 2000 MeV

Answer 1

Answer: (C)

200 MeV

Answer 2

E = B. E._Y + B.E._X – B.E._U = 2[117 × 8.5] – 236 × 7.6 = 200 MeV (apprx.)