Question

What is the empirical formula of the fructose found in honey?

Answer 1

The empirical formula of a chemical compound is the simplest positive integer ratio of atoms present in a compound. An empirical formula makes no mention of the arrangement or number of atoms. It is standard for many ionic compounds honey contains forty percent fructose and thirty percent glucose

Complete answer:
To find the empirical formula we must follow given steps:
-In any empirical formula problem you must first find the mass $$ of the elements in the compound.
-Then change the $$ to grams.
-Next, divide all the masses by their respective molar masses.
-Pick the smallest answer of the moles and divide all figures by that.
Honey gets its sweetness from the monosaccharides fructose and glucose, and has about the same relative sweetness as sucrose. Honey is higher in fructose than glucose. Fructose is sweeter than glucose, so you may be able to use a smaller amount of honey in your food or drink without sacrificing sweetness. The trace amounts of vitamins and minerals found in honey may also have added health benefits.
The empirical formula of the fructose $({C_6}{H_{12}}{O_6})$ found in honey is the simplest formula so divide the chemical formula by $6$ . Thus, $C{H_2}O$ .

Note:
The difference between the empirical formula and molecular formula is that the empirical formula of a compound gives the simplest ratio of the number of different atoms present, whereas the molecular formula gives the actual number of each different atom present in a molecule.