Question

What is the empirical formula of ${{B}_{3}}{{N}_{3}}{{H}_{6}}$?

Answer 1

There are two types of formula for a compound, i.e., molecular formula and empirical formula. The difference between the molecular formula and the empirical formula is that the actual formula of the compound is molecular but the simplest form of the molecular formula is known as the empirical formula. The given compound in the question is the molecular formula.

Complete answer:
The expression that shows the number and types of elements of a compound is known as the formula of the compound. There are two types of formulas for a compound, i.e., molecular formula and empirical formula. The difference between the molecular formula and the empirical formula is that the actual formula of the compound is molecular but the simplest form of the molecular formula is known as the empirical formula. And in the empirical formula, the simplest number should be the whole number.
So, the given formula in the question is ${{B}_{3}}{{N}_{3}}{{H}_{6}}$, this is the molecular formula.
From this formula we can see that there are:
3 atoms of boron atom
3 atoms of a nitrogen atom
6 atoms of a hydrogen atom
All the numbers are divisible by 3 then we will get the simplest number of atoms.
$\dfrac{3}{3}=1$ atom of boron will be present in the empirical formula
$\dfrac{3}{3}=1$ atom of nitrogen will be present in the empirical formula
$\dfrac{6}{3}=2$ atoms of hydrogen will be present in the empirical formula
So, the empirical formula will be $BN{{H}_{2}}$.

Note:
The relation between the molecular formula and empirical formula can be written as:
Molecular formula = n x empirical formula
Where n is an integer.