Question

What is the electronic configuration of $T{i^{2 + }}$?

Answer 1

We need to know that the cations are formed when an electron is lost. When this occurs there are less electron-electron repulsions and there is a greater net nuclear attraction per electron. So, the newly formed ion becomes a more condensed version of its neutral atom. Anions are formed when an electron is gained.

Complete answer:
As we know that the electron configuration of a neutral titanium atom is
$Ti$: $1{s^2}2{s^2}2{p^{6\;}}3{s^2}3{p^6}4{s^2}3{d^2}$
The two electrons that are lost when the $T{i^{2 + }}$ is formed will come from the 4s orbital, which means that the electron configuration of the cation is
$T{i^{2 + }}$:$1{s^2}2{s^2}2{p^6}3{s^2}3{p^6}3{d^2}$
Titanium is a chemical element with the symbol $Ti$ and atomic number twenty two. Its atomic weight is $47.867$ measured in Daltons. It is a lustrous transition metal with a silver color, low density, and high strength. Titanium is resistant to corrosion in sea water, aqua regia, and chlorine. Titanium is the ninth-most abundant element in Earth's crust ($0.63\%$ by mass) and the seventh-most abundant metal. It is present as oxides in most igneous rocks, in sediments derived from them, in living things, and natural bodies of water. Titanium is not as hard as some grades of heat-treated steel; it is non-magnetic and a poor conductor of heat and electricity.

Note:
We need to know that although titanium and zirconium have the same number of valence electrons and are in the same group in the periodic table, they differ in many chemical and physical properties. The two most useful properties of the metal are corrosion resistance and strength-to-density ratio, the highest of any metallic element.