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Question

Chemistry Question on Nernst Equation

What is the electrode potential (in VV ) of the following electrode at 25oC{{25}^{o}}C ? Ni2+(0.1M)Ni(s)N{{i}^{2+}}(0.1\,\,M)|Ni(s) (Standard reaction potential of Ni2+NiN{{i}^{2+}}|Ni is 0.25V,2.303RTF=0.06)-0.25\,\,V,\,\,\frac{2.303RT}{F}=0.06)

A

0.28V-0.28\,\,V

B

0.34V-0.34\,\,V

C

0.82V-0.82\,\,V

D

0.22V-0.22\,\,V

Answer

0.28V-0.28\,\,V

Explanation

Solution

Ecello=Ecello2.303RTnFlog[[Ni][Ni2+]]E_{cell}^{o}=E_{cell}^{o}-\frac{2.303RT}{nF}\log \left[ \frac{[Ni]}{[N{{i}^{2+}}]} \right] =0.250.062log(10.1)=-0.25-\frac{0.06}{2}\log \left( \frac{1}{0.1} \right) (n=2)(\because \,\,n=2) =0.250.03×1=-0.25-0.03\times 1 Ecell=0.28V{{E}_{cell}}=-0.28\,\,V