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Question: What is the domain and range of \[y=\dfrac{3}{x}\]?...

What is the domain and range of y=3xy=\dfrac{3}{x}?

Explanation

Solution

We are given with y=3xy=\dfrac{3}{x} which means that it has a variable in the denominator. To compute the domain and range of a function with a variable in the denominator, we must set the denominator equal to zero and then we have to exclude xx, we get an equation to be solved.

Complete step by step solution:
Now let us have a brief regarding the range and domain of functions. The domain means the set of possible input values. The graph of a domain consists of all the values that are shown upon the xaxisx-axis. The range is nothing but the set of possible output values. The graph of range consists of values that are represented upon the yaxisy-axis. We can find the domain and range by using graphs since both of them contain the required values that are to be plotted.
Now let us start finding the domain y=3xy=\dfrac{3}{x}.
While finding the domain, we shall not divide by 00 because it will give undefined value of y.
Since yy is defined xR:x0\forall x\in R:x\ne 0
R-\left\\{ 0 \right\\}
\therefore The domain of y=3xy=\dfrac{3}{x} would be (,0)(0,+)\left( -\infty ,0 \right)\cup \left( 0,+\infty \right)
Now let us find the range of y=3xy=\dfrac{3}{x}.
Let us consider that-

& \underset{x>0-}{\mathop{\lim }}\,y=-\infty \\\ & \underset{x<0+}{\mathop{\lim }}\,=+\infty \\\ \end{aligned}$$ $$\therefore $$ The range of $$y=\dfrac{3}{x}$$ is $$\left( -\infty ,+\infty \right)$$ **Note:** The rule of the domain is that if a function contains a square root, we must set the equation inside the square root greater or equal to zero and solve. The resulting answer would be the domain. If the function contains a fraction, set the denominator not equal to zero. By solving this, we obtain the domain. The graph of $$y=\dfrac{3}{x}$$ is ![](https://www.vedantu.com/question-sets/154d17db-1b8c-4a6f-b89d-1f4b1a8338dc4989031874583530641.png)