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Question: What is the domain and range of \(\arccos \left( x-1 \right)\) ?...

What is the domain and range of arccos(x1)\arccos \left( x-1 \right) ?

Explanation

Solution

We can define the domain of a function as the complete step of possible values of the independent variable. So, we can say that the domain is the set of all possible xx values which will make the function ‘work’ and will give the output of yy as a real number. And the range of a function is the complete set of all possible resulting values of the dependent variable (yy usually), after we have substituted the domain.

Complete step-by-step solution:
According to our question it is asked to calculate the domain and range of arccos(x1)\arccos \left( x-1 \right) or cos1(x1){{\cos }^{-1}}\left( x-1 \right). For determining the range and the domain we have to see the domain and the range of inverse cosine function. The range of an inverse cosine function is defined as 0yπ0\le y\le \pi . And this is fixed for all inverse cosine functions. And the domain for an inverse cosine function must be between -1 to 1. Both the range and the domain are related to each other. The range of any function decides the values from where the function will show and the domain decides the quantity of that graph of the function.
So, if we see in the question then it is clear that it is asked to determine the domain and the range of inverse cos(x1)\cos \left( x-1 \right). So, the range of inverse cosine functions always remains the same and that is 0yπ0\le y\le \pi . Because these functions vary between the first and second quadrant always. So, the range is 0yπ0\le y\le \pi that can be written as [0,π]\left[ 0,\pi \right].
The domain of the inverse cosine function is -1 to 1. And this is because the values of an inverse function always varies between -1 to 1. But our function is inverse cos(x1)\cos \left( x-1 \right). So, we have to add our domain from 1. If we increase the domain of arccos(x)\arccos \left( x \right) by 1, then the domain is,
1+1x1+1-1+1\le x\le 1+1
So, we can write it as 0x20\le x\le 2.
So, the domain of arccos(x1)\arccos \left( x-1 \right) is equal to [0,2]\left[ 0,2 \right] and the range is [0,π]\left[ 0,\pi \right].

Note: We must know the trigonometry concepts to solve this question. The domain where the xx value ranges and the range where the yy value ranges. Here the function is a form of trigonometric function. So, we have to see the values in which the domain is defined that will be the value of range for this function.