Question
Question: What is the distance between the lines 4x + 3y = 11 and 8x + 6y = 15? (a). \[\dfrac{7}{2}\] (b)....
What is the distance between the lines 4x + 3y = 11 and 8x + 6y = 15?
(a). 27
(b). 4
(c). 107
(d). None of these
Solution
Check if the two lines are parallel using the condition a2a1=b2b1. Then use the distance between two parallel lines formula for the lines ax+by+c1=0 and ax+by+c2=0 is given as d=a2+b2∣c1−c2∣ to find the answer.
Complete step-by-step answer:
We are given the equations of the two lines as 4x + 3y = 11 and 8x + 6y = 15.
The condition for two lines a1x+b1y+c1=0 and a2x+b2y+c2=0 to be parallel is given by:
a2a1=b2b1
Let us check this condition for the lines 4x + 3y = 11 and 8x + 6y = 15.
a2a1=84
a2a1=21..............(1)
b2b1=63
b2b1=21............(2)
From equations (1) and (2), we have:
a2a1=b2b1
Hence, the two lines are parallel.
For finding the distance between the two parallel lines, we first express the two equations such that the coefficients of x and y are equal.
We multiply the equation 4x + 3y = 11 by 2, then, we have:
2(4x+3y)=2(11)
Simplifying, we have:
8x+6y=22
Now, we use the formula for calculating the distance between two parallel lines ax+by+c1=0 and ax+by+c2=0 given as follows:
d=a2+b2∣c1−c2∣
From the equations of the lines, we have:
c1=−22
c2=−15
a = 8
b = 6
Then, we have:
d=82+62∣−22−(−15)∣
Simplifying, we have:
d=64+36∣−22+15∣
d=100∣−7∣
d=107
Hence, the correct answer is option (c).
Note: You may forget to convert the equations such that both equations have same coefficients of x and y, in that case, you get a wrong answer. Always convert both equations into similar form.