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Question: What is the distance between the lines 4x + 3y = 11 and 8x + 6y = 15? (a). \[\dfrac{7}{2}\] (b)....

What is the distance between the lines 4x + 3y = 11 and 8x + 6y = 15?
(a). 72\dfrac{7}{2}
(b). 4
(c). 710\dfrac{7}{{10}}
(d). None of these

Explanation

Solution

Check if the two lines are parallel using the condition a1a2=b1b2\dfrac{{{a_1}}}{{{a_2}}} = \dfrac{{{b_1}}}{{{b_2}}}. Then use the distance between two parallel lines formula for the lines ax+by+c1=0ax + by + {c_1} = 0 and ax+by+c2=0ax + by + {c_2} = 0 is given as d=c1c2a2+b2d = \dfrac{{|{c_1} - {c_2}|}}{{\sqrt {{a^2} + {b^2}} }} to find the answer.

Complete step-by-step answer:

We are given the equations of the two lines as 4x + 3y = 11 and 8x + 6y = 15.

The condition for two lines a1x+b1y+c1=0{a_1}x + {b_1}y + {c_1} = 0 and a2x+b2y+c2=0{a_2}x + {b_2}y + {c_2} = 0 to be parallel is given by:

a1a2=b1b2\dfrac{{{a_1}}}{{{a_2}}} = \dfrac{{{b_1}}}{{{b_2}}}

Let us check this condition for the lines 4x + 3y = 11 and 8x + 6y = 15.

a1a2=48\dfrac{{{a_1}}}{{{a_2}}} = \dfrac{4}{8}

a1a2=12..............(1)\dfrac{{{a_1}}}{{{a_2}}} = \dfrac{1}{2}..............(1)

b1b2=36\dfrac{{{b_1}}}{{{b_2}}} = \dfrac{3}{6}

b1b2=12............(2)\dfrac{{{b_1}}}{{{b_2}}} = \dfrac{1}{2}............(2)

From equations (1) and (2), we have:

a1a2=b1b2\dfrac{{{a_1}}}{{{a_2}}} = \dfrac{{{b_1}}}{{{b_2}}}

Hence, the two lines are parallel.

For finding the distance between the two parallel lines, we first express the two equations such that the coefficients of x and y are equal.

We multiply the equation 4x + 3y = 11 by 2, then, we have:

2(4x+3y)=2(11)2(4x + 3y) = 2(11)

Simplifying, we have:

8x+6y=228x + 6y = 22

Now, we use the formula for calculating the distance between two parallel lines ax+by+c1=0ax + by + {c_1} = 0 and ax+by+c2=0ax + by + {c_2} = 0 given as follows:

d=c1c2a2+b2d = \dfrac{{|{c_1} - {c_2}|}}{{\sqrt {{a^2} + {b^2}} }}

From the equations of the lines, we have:

c1=22{c_1} = - 22

c2=15{c_2} = - 15

a = 8

b = 6

Then, we have:

d=22(15)82+62d = \dfrac{{| - 22 - ( - 15)|}}{{\sqrt {{8^2} + {6^2}} }}

Simplifying, we have:

d=22+1564+36d = \dfrac{{| - 22 + 15|}}{{\sqrt {64 + 36} }}

d=7100d = \dfrac{{| - 7|}}{{\sqrt {100} }}

d=710d = \dfrac{7}{{10}}

Hence, the correct answer is option (c).

Note: You may forget to convert the equations such that both equations have same coefficients of x and y, in that case, you get a wrong answer. Always convert both equations into similar form.