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Question

Question: What is the differentiation of \[uv\]?...

What is the differentiation of uvuv?

Explanation

Solution

Differentiation of uvuv can be obtained by the product rule. Product rule is the formula used to find the derivatives of a product of two or more functions. if u,vu,v are two functions of xx, then the derivative of product of uvuv is given by ddx(uv)=uddx(v)+vddx(u)\dfrac{d}{dx}\left( uv \right)=u\dfrac{d}{dx}\left( v \right)+v\dfrac{d}{dx}\left( u \right).

Complete step-by-step solution:
From the question it is clear that we have to write the differentiation of uvuv. Which we can simply write from the product rule.
Let us assume u,vu,v are two functions of xx.
Product rule is the formula used to find the derivatives of a product of two or more functions.
When the first function is multiplied by the derivative of the second function plus the second function multiplied by the derivative of the first function is known as product rule. This is an easy way of remembering and easy writing.
Let us assume uvuv as yy
y=uv\Rightarrow y=uv……………(1)
From the question we were asked to find the derivative of uvuv. So, finding dydx\dfrac{dy}{dx} is equal to finding ddx(uv)\dfrac{d}{dx}\left( uv \right).
So,
dydx=ddx(uv)\Rightarrow \dfrac{dy}{dx}=\dfrac{d}{dx}\left( uv \right)……………….(2)
Using product rule, we can write the equation (2) as
ddx(uv)=uddx(v)+vddx(u)\Rightarrow \dfrac{d}{dx}\left( uv \right)=u\dfrac{d}{dx}\left( v \right)+v\dfrac{d}{dx}\left( u \right)
So finally, we can conclude that derivative of uvuvis uddx(v)+vddx(u)u\dfrac{d}{dx}\left( v \right)+v\dfrac{d}{dx}\left( u \right).

Note: Students should be careful while applying product rules. Small errors in the application of product rule may lead to doing this question wrong and may get the wrong answer. Many students may have misconception that ddx(uv)=ddx(u)×ddx(v)\dfrac{d}{dx}\left( uv \right)=\dfrac{d}{dx}\left( u \right)\times \dfrac{d}{dx}\left( v \right), which is completely wrong formula. Using this wrong formula may lead to this question wrong.