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Question

Question: What is the derivative of \[{{\tan }^{2}}y\]?...

What is the derivative of tan2y{{\tan }^{2}}y?

Explanation

Solution

In this problem, we have to find the derivative of tan2y{{\tan }^{2}}y. Here we can use the chain rule as we have two functions in the given problem. Here we have an inside function tany\tan y and the outside function tan2y{{\tan }^{2}}y, where we have to find the derivative of the outside function first and then we have to derive the inside function and then multiply them to get the final answer.

Complete step-by-step solution:
Here we have to find the derivative of tan2y{{\tan }^{2}}y.
We can now use the differentiation formulas to find the derivative of the given problem.
Here we have to use the chain rule as we have two functions.
We have an inside function tany\tan y and the outside function tan2y{{\tan }^{2}}y, where we have to find the derivative of the outside function first and then we have to derive the inside function
We know that, ddxtan2u=2tan1ududx\dfrac{d}{dx}{{\tan }^{2}}u=2{{\tan }^{1}}u\dfrac{du}{dx}
We can apply this to the outside function tan2y{{\tan }^{2}}y, we get
2tany\Rightarrow 2\tan y
We know that ddxtany=sec2ydudx\dfrac{d}{dx}\tan y={{\sec }^{2}}y\dfrac{du}{dx}
We can now differentiate the inside function tany\tan y, we get
2tanysec2y\Rightarrow 2\tan y{{\sec }^{2}}y
Therefore, the derivative of tan2y{{\tan }^{2}}y is 2tanysec2y2\tan y{{\sec }^{2}}y.

Note: We should always remember the chain rule, as we have two functions, we should take them as inside function and outside function. We can then find the derivatives for both inside and the outside functions and multiply them to get the final answer. We should also remember the formulas of derivation as we differentiate tany\tan y, we get sec2y{{\sec }^{2}}y.