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Question

Question: What is the derivative of \({{\tan }^{2}}x\)?...

What is the derivative of tan2x{{\tan }^{2}}x?

Explanation

Solution

We are asked to find the derivative of tan2x{{\tan }^{2}}x. We are going to find the derivative of tan2x{{\tan }^{2}}x by using chain rule. In chain rule, we will assume tanx\tan x as “t” and then we are going to take the derivative with respect to “t”. Now, we are going to find the relation between “t” and “x” by equating “t” to tanx\tan x and then differentiating on both sides. Then write “t” in terms of x.

Complete step-by-step solution:
In the above problem, we have asked to find the derivative of tan2x{{\tan }^{2}}x. For that, we are going to assume tanx=t\tan x=t. Now, substituting tanx\tan x as “t” in tan2x{{\tan }^{2}}x we get,
t2{{t}^{2}}
Taking derivative of the above expression with respect to “c” we get,
2tdtdx2t\dfrac{dt}{dx} ………… (1)
The above derivative comes because we know that the differentiation of tn{{t}^{n}} is given as:
dtndt=ntn1\dfrac{d{{t}^{n}}}{dt}=n{{t}^{n-1}}
Now, we are going to differentiate on both the sides of tanx=t\tan x=t we get,
sec2xdx=dt{{\sec }^{2}}xdx=dt
Dividing dxdx on both the sides of the above equation we get,
sec2x=dtdx{{\sec }^{2}}x=\dfrac{dt}{dx}
Using the above relation in eq. (1) we get,
2tsec2x2t{{\sec }^{2}}x
Substituting the value of “t” as tanx\tan x in the above equation we get,
2(tanx)sec2x2\left( \tan x \right){{\sec }^{2}}x
Hence, we have solved the derivative of tan2x{{\tan }^{2}}x as 2tanxsec2x2\tan x{{\sec }^{2}}x.

Note: To solve the above problem, you should know the derivative of tanx\tan x with respect to x and also how to differentiate xn{{x}^{n}} with respect to x otherwise we cannot move forward in the above problem. Also, while finding the derivative of tan2x{{\tan }^{2}}x, you might forget to write 2 in the final answer so make sure you have written the number 2 in the final answer.