Question
Question: What is the derivative of \({\sin ^2}\left( {5x} \right)\)?...
What is the derivative of sin2(5x)?
Solution
In the given problem, we are required to differentiate sin2(5x) with respect to x. The given function is a composite function, so we will have to apply the chain rule of differentiation in the process of differentiation. So, differentiation of sin2(5x) with respect to x will be done layer by layer. Also the derivative of sinxwith respect to x must be remembered.
Complete step by step solution:
So, Derivative of sin2(5x) with respect to xcan be calculated as dxd(sin2(5x)) .
Now, dxd(sin2(5x))
Now, Let us assume u=sin5x. So substituting sin5x as u, we get,
= dxd(u2)
Now, we know the power rule of differentiation as dxd(xn)=nxn−1. So, we get,
=2u(dxdu)
Now, putting back uas sin5x, we get,
=2sin5x(dxd(sin5x)) because dxdu=dxd(sin5x)
Now, taking t=5x. We get,
=2sin5x(dxd(sint))
We know that derivative of sine is equal to cosine. So, we get,
=2sin5x[cost×dxdt]
Now, putting back the value of t in the equation, we get,
=2sin5x[cos(5x)×dxd(5x)]
Using the power rule of differentiation again, we get,
=2sin5x[cos(5x)×5]
Simplifying the expression, we get,
=10sin5xcos5x
Now, we know the double angle formula for sine as sin2x=2sinxcosx. Hence, we get,
=5sin(10x)
So, the derivative of sin2(5x) with respect to x is sin10x.
Note:
The chain rule of differentiation involves differentiating a composite by introducing new unknowns to ease the process and examine the behaviour of function layer by layer. Answer to the given problem can also be reported as 10sin5xcos5x before applying the double angle formula for sine function, but it is better to provide the final answer in the condensed form.