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Question

Question: What is the derivative of \[{e^{5x}}\] \[?\]...

What is the derivative of e5x{e^{5x}} ??

Explanation

Solution

Hint : Suppose uu and vv are functions of xx only. Then differentiation has the following rules:
1.The derivative of the constant function is equal to zero.
2.Product rule: ddx(u×v)=v×ddx(u)+u×ddx(v)\dfrac{d}{{dx}}\left( {u \times v} \right) = v \times \dfrac{d}{{dx}}\left( u \right) + u \times \dfrac{d}{{dx}}\left( v \right) .
3.Quotient rule: ddx(uv)=v×ddx(u)u×ddx(v)v2\dfrac{d}{{dx}}\left( {\dfrac{u}{v}} \right) = \dfrac{{v \times \dfrac{d}{{dx}}\left( u \right) - u \times \dfrac{d}{{dx}}\left( v \right)}}{{{v^2}}} .
4.If uu is a function of vv, Then ddx(u(v))=ddv(u(v))×dvdx\dfrac{d}{{dx}}\left( {u(v)} \right) = \dfrac{d}{{dv}}\left( {u(v)} \right) \times \dfrac{{dv}}{{dx}} and ddx(uv(x))=ddv(uv(x))×dvdx\dfrac{d}{{dx}}\left( {{u^{v(x)}}} \right) = \dfrac{d}{{dv}}\left( {{u^{v(x)}}} \right) \times \dfrac{{dv}}{{dx}}

Complete step by step solution:
The composite function is a function where one function is substituting into another function. Since we know that ddx(ex)=ex\dfrac{d}{{dx}}\left( {{e^x}} \right) = {e^x} .
Note that 4th{4^{th}} rule is known as the chain rule. If the function is composed of three functions, say uu, vv and ww are functions of xx . Then the derivative of the composition of three function is defined as follows
ddx(u(v(w(x))))=dudv.dvdw.dwdx\dfrac{d}{{dx}}\left( {u(v(w(x)))} \right) = \dfrac{{du}}{{dv}}.\dfrac{{dv}}{{dw}}.\dfrac{{dw}}{{dx}} .
Given e5x{e^{5x}} ----(1)
Differentiating with respect to xx both sides of the equation (1), we get
ddx(e5x)=e5xddx(5x)=5e5x\dfrac{d}{{dx}}\left( {{e^{5x}}} \right) = {e^{5x}}\dfrac{d}{{dx}}\left( {5x} \right) = 5{e^{5x}}
Hence, the derivative of the given function cosx2\cos {x^2} is 5e5x5{e^{5x}} .
So, the correct answer is “ 5e5x5{e^{5x}} ”.

Note : A differential equation is the equation which contains dependent variables, independent variables and derivatives of the dependent variables with respect to the independent variables. Since differential equations are classified into two types, Ordinary differential equations where dependent variables depend on only one independent variable and Partial differential equations where dependent variables depend on two or more independent variables