Solveeit Logo

Question

Question: What is the derivative of \(\dfrac{\pi }{x}\) ?...

What is the derivative of πx\dfrac{\pi }{x} ?

Explanation

Solution

To solve this question we need to know the concept of differentiation and its formula. The formula used to evaluate the above function is d(xn)dx=nxn1\dfrac{d\left( {{x}^{n}} \right)}{dx}=n{{x}^{n-1}} . The function consists of the constant variable π\pi .

Complete step by step solution:
The question asks us to find the derivative of πx\dfrac{\pi }{x} which means we need to differentiate the function given to us which is πx\dfrac{\pi }{x} . Here π\pi is a constant with Value 3.14 so while of the differentiation of πx\dfrac{\pi }{x} will be used as the constant so we will be just differentiating of 1x\dfrac{1}{x} with respect to xx.
On differentiating the function πx\dfrac{\pi }{x} we get:
d(πx)dx\Rightarrow \dfrac{d\left( \dfrac{\pi }{x} \right)}{dx}
In the above function π\pi will be taken out of the function as given below:
πd(1x)dx\Rightarrow \pi \dfrac{d\left( \dfrac{1}{x} \right)}{dx}
The above fraction that need to be differentiated will be reciprocal and the power would as a result change to 1-1, this could be written as:
πd(x1)dx\Rightarrow \pi \dfrac{d\left( {{x}^{-1}} \right)}{dx}
To solve the above expression we will use the formula, d(xn)dx=nxn1\dfrac{d\left( {{x}^{n}} \right)}{dx}=n{{x}^{n-1}} where value of “n” is 1-1. On applying the above formula to the function we get:
π(1)x11\Rightarrow \pi \left( -1 \right){{x}^{-1-1}}
On further calculation the above expression becomes:
πx2\Rightarrow -\pi {{x}^{-2}}
The above answer could be changed to the term with the positive power of xx by doing its reciprocal.
πx2\Rightarrow -\dfrac{\pi }{{{x}^{2}}}

\therefore The derivative of πx\dfrac{\pi }{x} is πx2\dfrac{-\pi }{{{x}^{2}}}

Note: The above question π\pi is constant in the function given to us. Do get confused with the value of π\pi . We need to remember the formula for the differentiation of the function given above. Do remember that the reciprocal of a value changes the sign of the power. For example if a function or number a1{{a}^{-1}} is reciprocal the power changes to positive sign like (1a)1{{\left( \dfrac{1}{a} \right)}^{1}}.