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Question

Question: What is the derivative of \({{5}^{x}}\) ?...

What is the derivative of 5x{{5}^{x}} ?

Explanation

Solution

To obtain the derivative of 5x{{5}^{x}} we will use logarithm function. Firstly we will let y=5xy={{5}^{x}} and then take a logarithm function on both sides of the equation. Next we will use the logarithm property and simplify our equation. Finally we will differentiate the equation with respect to xx using implicit differentiation and get the desired answer.

Complete step-by-step answer:
To find the derivative of 5x{{5}^{x}} we will let,
y=5xy={{5}^{x}}…..(1)\left( 1 \right)
Taking log\log both sides we get,
log(y)=log(5x)\log \left( y \right)=\log \left( {{5}^{x}} \right)
Using logarithm property on right hand side which is given as:
log(ab)=blog(a)\log \left( {{a}^{b}} \right)=b\log \left( a \right)
Where a,ba,b can be any constant or variable
We get,
log(y)=xlog(5)\log \left( y \right)=x\log \left( 5 \right)…..(2)\left( 2 \right)
Differentiating equation (2) with respect to xx using implicit differentiation we get,
log(y)=xlog(5) 1y×dydx=log(5)×d(x)dx 1y×y=log(5)×1 y=ylog(5) \begin{aligned} & \log \left( y \right)=x\log \left( 5 \right) \\\ & \Rightarrow \dfrac{1}{y}\times \dfrac{dy}{dx}=\log \left( 5 \right)\times \dfrac{d\left( x \right)}{dx} \\\ & \Rightarrow \dfrac{1}{y}\times y=\log \left( 5 \right)\times 1 \\\ & \therefore {y}'=y\log \left( 5 \right) \\\ \end{aligned}
Where, Primes ()\left( ' \right) denote the differentiation with respect to xx
Replacing yy value from equation (1) in above equation we get,
y=5xlog(5) (5x)=5xlog(5) \begin{aligned} & \Rightarrow {{y}^{'}}={{5}^{x}}\log \left( 5 \right) \\\ & \therefore {{\left( {{5}^{x}} \right)}^{'}}={{5}^{x}}\log \left( 5 \right) \\\ \end{aligned}
Hence, the derivative of 5x{{5}^{x}} is 5xlog(5){{5}^{x}}\log \left( 5 \right)

Note: An exponential function is expressed as f(x)=axf\left( x \right)={{a}^{x}} where aa is a positive real number and xx is an argument which is present as an exponent. The growth rate of such a function is directly proportional to the value of the function. Implicit differentiation is done when we can’t find the derivative of yy in xx term, that is xx doesn’t lead to yy directly. We can use another method to find the derivative of the exponential function by using the direct formula of it. To find the derivative of 5x{{5}^{x}} we can also use the derivative formula for exponential function as,
The formula is given below:
ddxax=axlogea\dfrac{d}{dx}{{a}^{x}}={{a}^{x}}{{\log }_{e}}a….(3)\left( 3 \right) For aRa\in R
On comparing the above equation by 5x{{5}^{x}} we get,
a=5a=5
On substituting the above value in equation (3) we get,
ddx5x=5xloge5\Rightarrow \dfrac{d}{dx}{{5}^{x}}={{5}^{x}}{{\log }_{e}}5
Hence, the derivative of 5x{{5}^{x}} is5xloge5{{5}^{x}}{{\log }_{e}}5.