Question
Question: What is the density of hydrogen gas using the ideal gas law?...
What is the density of hydrogen gas using the ideal gas law?
Solution
Hint : The ideal gas law, also known as the general gas equation, is the equation of state for a hypothetical ideal gas. Although it has several shortcomings, it is a rational estimate of the behaviour of such gases under a variety of conditions.
Complete Step By Step Answer:
The chemical element with atomic number 1 and an atomic mass of 1.00794$amu,thelightestofallknownatoms,ishydrogen,themostcommonelementintheuniverse.Itoccursintheformofadiatomicgas.Tofindthedensityofhydrogengasweusetheidealgaslaw.TheIdealgaslawstatesthat:PV = nRTHere,Pistheabsolutepressureofagas,Visthevolumeitoccupies,nisthenumberofatomsandmoleculesinthegasAndTisitsabsolutetemperature.Itisknowntousthatn = \dfrac{m}{M},Misthemolarmassandmisthemassofthesubstancemeasuredinthegrams.Substitutingtheaboveequationinthegaslaw,weget:pV = \dfrac{m}{M}RT \Rightarrow pM = \dfrac{m}{V}RTWeknowthatthedensityofthecompound\rho = \dfrac{m}{V}.Thus,bysubstitutingthisrelationintheaboveequationbecomes: \Rightarrow pM = \rho RTTherefore, \Rightarrow \rho = \dfrac{{pM}}{{RT}}Tofindthedensityofhydrogengas,weusethestandardconditionsofP = 1atmandT = 298K.Weknowthatthemolarmassof{H_2} = 2.012gmo{l^{ - 1}}Substitutingthevaluestotheaboveequation,{\rho _{{H_2}}} = \dfrac{{1 \cdot atm \times 2.016 \cdot g \cdot mo{l^{ - 1}}}}{{0.0821 \cdot \dfrac{{L \cdot atm}}{{K \cdot mol}} \times 298 \cdot K}} \cong 0.1 \cdot g \cdot {L^{ - 1}}Thus,thedensityofhydrogengasfoundusingtheidealgaslawis0.1g{L^{ - 1}}$
Note :
The term "ideal gas" refers to a hypothetical gas composed of molecules that follow a series of rules: The molecules of an ideal gas are neither attracted nor repellent to one another. The only interaction ideal gas molecules can have will be an elastic collision when they collide with each other or the container's sides.