Question

What is the density of a block of marble that occupies $310c{{m}^{3}}$ and has a mass of $853\text{ }g$ ?

Answer 1

Use the given information in question and put it in the formula of density which is:
$density(\rho )=\dfrac{mass\text{ of given substance(m)}}{volume\text{ of given substance(V)}}$

Complete answer:
Now it is given in question that the mass of marble block is $853\text{ }g$ that means the value of m = $853\text{ }g$ and the volume occupied by the marble block is given which is $310c{{m}^{3}}$ that means the value of V = $310c{{m}^{3}}$ , now putting the value of m and V in the formula of density which is
$density(\rho )=\dfrac{mass\text{ of given substance(m)}}{volume\text{ of given substance(V)}}$
Putting the values we will get our answer:
$\rho =\dfrac{853}{310}g\text{ c}{{\text{m}}^{-3}}$
$\rho =2.751g\text{ c}{{\text{m}}^{-3}}$
Hence, it is our answer.

Note:
The unit of density depends on the fact that in which unit the mass and the volume is given so keep the unit of mass and volume in check.