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Question

Physics Question on Moving charges and magnetism

What is the correct value of Bohr magneton?

A

8.99×10−24 A m28.99 \times 10^{-24}\, A\, m^{2}

B

9.27×10−24 A m29.27 \times 10^{-24}\, A\, m^{2}

C

5.66×10−24 A m25.66 \times 10^{-24}\, A\, m^{2}

D

9.27×10−28 A m29.27 \times 10^{-28}\, A\, m^{2}

Answer

9.27×10−24 A m29.27 \times 10^{-24}\, A\, m^{2}

Explanation

Solution

Bohr Magnetron (μl)min=μB=e4πmeh\left(\mu_{l}\right)_{min} = \mu_{B} = \frac{e}{4\pi m_{e}}h Here, e=1.6×10−19 Ce=1.6 \times 10^{-19}\, C, h=6.64×10−34 J sh=6.64 \times 10^{-34}\,J\, s me=9.1×10−31 kgm_{e} =9.1 \times 10^{-31}\,kg ∴μB=1.60×10−19×6.64×10−344×3.14×9.1×10−31\therefore\mu_{B}=\frac{1.60\times10^{-19}\times6.64\times10^{-34}}{4\times3.14\times9.1\times10^{-31}} =9.27×10−24 A m2=9.27\times10^{-24}\,A\,m^{2}