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Question: What is the conjugate base of \[{H_2}P{O_4}^ - \]? \[ A.{H_2}P{O_4} \\\ B.{H_2}P{O_4}^{2 -...

What is the conjugate base of H2PO4{H_2}P{O_4}^ - ?

A.H2PO4 B.H2PO42 C.H3O+ D.PO43  A.{H_2}P{O_4} \\\ B.{H_2}P{O_4}^{2 - } \\\ C.{H_3}{O^ + } \\\ D.P{O_4}^{ - 3} \\\
Explanation

Solution

We can define conjugate base as a base which is formed after an acid loses its hydrogen. Acid has a tendency to donate protons or accept an electron whereas a base has a tendency to accept protons or we can say to donate an electron.

Complete step by step answer:
Let’s start with discussing the conjugate base; conjugate base can be defined as a base which is formed after acid loses its hydrogen. So, whenever acid loses its hydrogen ion the residue that is left is termed as conjugate base as it has a tendency to accept a hydrogen atom or to be more accurate it has a tendency to donate an electron. Acid has a tendency to donate protons or accept an electron whereas a base has a tendency to accept protons or we can say to donate an electron.
Now coming to given question we have to find the conjugate base of the acid H2PO42{H_2}P{O_4}^{2 - }
Writing its chemical equation where it loses its H+{H^ + } ion and forms a conjugate base is
H2PO4H+ + HPO42{H_2}P{O_4}^ - \to {H^ + }{\text{ }} + {\text{ }}HP{O_4}^{2 - }
As we can see the conjugate base formed is HPO42HP{O_4}^{2 - }, which is formed after the acid H2PO4{H_2}P{O_4}^ - losses an H+{H^ + } ion.

Hence, Option B is the correct answer.

Note:
We must know that the conjugate base and conjugate acid are two components which are formed after the respected acid and base loses their H+{H^ + } and OHO{H^ - } ions. They gain a tendency to obtain what they have lost, meaning in case of a conjugate base it will try to gain a proton to again become an acid and a conjugate acid will try to gain an electron to again become a base.