Question
Question: What is the charge on the complex [Cr(C2O4)2(H2O)2] formed by Cr(III)?...
What is the charge on the complex [Cr(C2O4)2(H2O)2] formed by Cr(III)?
A
+3
B
+1
C
+2
D
–1
Answer
–1
Explanation
Solution
H2O is neutral, chromium oxidation state i.e. charge is +3 and oxalato anion has –2 charge; due to two C2O42– it will be – 4 and net charge on the complex is algebraic sum of the charge on metal ion and ligands present in the coordination sphere. So 3 + 2 × (–2) = – 1. So the formulae of complex is [Cr(C2O4)(H2O)]–.