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Question: What is the change in temperature on the Fahrenheit scale and on the Kelvin scale, of an iron piece,...

What is the change in temperature on the Fahrenheit scale and on the Kelvin scale, of an iron piece, is heated from 30C{30^ \circ }C to 90C{90^ \circ }C .
(A) 108F,60K{108^ \circ }F,60K
(B) 100F,55K{100^ \circ }F,55K
(C) 100F,65K{100^ \circ }F,65K
(D) 60F,108K{60^ \circ }F,108K

Explanation

Solution

To solve this question we need to know the formula to convert the unit of temperature from degree centigrade to degree Fahrenheit or Kelvin. After the conversion of the units of the temperature, we need to find the difference between the two given temperatures.

Formula used:
F=95(C)+32^\circ F = \dfrac{9}{5}(^\circ C) + 32
K=C+273K{ = ^\circ }C + 273
where, C^ \circ C is the temperature given in degree centigrade,
F^ \circ F is the temperature given in degree Fahrenheit, and
KK is the temperature given in Kelvin.

Complete step by step answer:
Let us first convert the two temperature given in degree centigrade into degree Fahrenheit using the formula,
F=95(C)+32^\circ F = \dfrac{9}{5}(^\circ C) + 32 ……………. (1)(1)
where, C^ \circ C is the temperature given in degree centigrade,
F^ \circ F is the temperature given in degree Fahrenheit.
Let the initial temperature be Ci=30C{C_i} = {30^ \circ }C . Putting this value in the above equation (1)(1) we get,
Fi=95(30)+32^ \circ {F_i} = \dfrac{9}{5}\left( {30} \right) + 32
Fi=(9×6)+32{ \Rightarrow ^ \circ }{F_i} = (9 \times 6) + 32
Upon further solving the equation we get,
Fi=54+32^ \circ {F_i} = 54 + 32
Fi=86F{ \Rightarrow ^ \circ }{F_i} = {86^ \circ }F
Let the final temperature be Cf=90C{C_f} = {90^ \circ }C . Putting this value in the above equation (1)(1) we get,
Ff=95(90)+32^ \circ {F_f} = \dfrac{9}{5}\left( {90} \right) + 32
Ff=(9×18)+32{ \Rightarrow ^ \circ }{F_f} = (9 \times 18) + 32
Upon further solving the equation we get,
Ff=162+32^ \circ {F_f} = 162 + 32
Ff=194F{ \Rightarrow ^ \circ }{F_f} = {194^ \circ }F
Therefore the change in temperature in degree Fahrenheit,
F=FfFi^ \circ F{ = ^ \circ }{F_f}{ - ^ \circ }{F_i}
F=19486^ \circ F = 194 - 86
F=108F{ \Rightarrow ^ \circ }F = {108^ \circ }F
Now, let us convert the two temperature given in degree centigrade into Kelvin using the formula,
K=C+273K{ = ^ \circ }C + 273
where, KK is the temperature given in Kelvin.
Using the value Ci=30C{C_i} = {30^ \circ }C , we get the initial temperature in Kelvin as,
Ki=30+273{K_i} = 30 + 273
Ki=303K\Rightarrow {K_i} = 303K
Now, using the value Cf=90C{C_f} = {90^ \circ }C , we get the final temperature in Kelvin as,
Kf=90+273{K_f} = 90 + 273
Kf=363K\Rightarrow {K_f} = 363K
Therefore the change in temperature in Kelvin is given as,
K=KfKiK = {K_f} - {K_i}
K=363303\Rightarrow K = 363 - 303
K=60K\therefore K = 60K
Hence the correct option is option (A) 108F,60K{108^ \circ }F,60K .

Note:
As we can see from the above solution that the difference in temperature in degree centigrade and Kelvin is equal. Hence while solving questions where a temperature change is involved, conversion of the unit from degree centigrade to Kelvin, or vice versa is not required. But this is not the case for degrees Fahrenheit.