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Question: What is the change in oxidation number of Pb during conversion of $PbO_2$ to $Pb(NO_3)_2$ ?...

What is the change in oxidation number of Pb during conversion of PbO2PbO_2 to Pb(NO3)2Pb(NO_3)_2 ?

A

+2 to +4

B

+4 to +2

C

+4 to +7

D

+4 to +6

Answer

+4 to +2

Explanation

Solution

For PbO2PbO_2:

Let oxidation state of Pb = xx. With oxygen at 2-2,

x+2(2)=0    x=+4.x + 2(-2) = 0 \implies x = +4.

For Pb(NO3)2Pb(NO_3)_2:

Since NO3NO_3^- has a charge of 1-1, and there are 2 nitrate ions,

x+2(1)=0    x=+2.x + 2(-1) = 0 \implies x = +2.

Thus, the oxidation number of Pb changes from +4+4 to +2+2.