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Question

Question: What is the centre of mass of a non-uniform rod of length \[L\] which has mass per unit length \(\la...

What is the centre of mass of a non-uniform rod of length LL which has mass per unit length λ=kx2L\lambda = \dfrac{{k{x^2}}}{L} where kk is a constant and xx is the distance from the one end?
(A) 3L4\dfrac{{3L}}{4}
(B) L8\dfrac{L}{8}
(C) kL\dfrac{k}{L}
(D) 3kL\dfrac{{3k}}{L}

Explanation

Solution

Hint As given that λ=kx2L\lambda = \dfrac{{k{x^2}}}{L}
dm=kx2Ldx\therefore dm = \dfrac{{k{x^2}}}{L}dx
To find the centre of mass of non-uniform rod of length LL so, we will use the formula-
XCM=0Lxdm0Ldm(1){X_{CM}} = \dfrac{{\int\limits_0^L {xdm} }}{{\int\limits_0^L {dm} }} \cdots (1)
where, XCM{X_{CM}} is the centre of mass of object
LL is the length of object

Complete step-by-step answer:
According to the question, it is given that the length of rod is LL so, we will take the limit for integration in the equation (1)(1) we get
XCM=0Lxdm0Ldm{X_{CM}} = \dfrac{{\int\limits_0^L {xdm} }}{{\int\limits_0^L {dm} }}
Now, putting the value of dmdm in the above equation
XCM=0Lxkx2Ldx0Lkx2Ldx{X_{CM}} = \dfrac{{\int\limits_0^L {x\dfrac{{k{x^2}}}{L}dx} }}{{\int\limits_0^L {\dfrac{{k{x^2}}}{L}dx} }}
Integrating both sides with respect to xx, we get
XCM=kL[x44]0LkL[x33]0L{X_{CM}} = \dfrac{{\dfrac{k}{L}\left[ {\dfrac{{{x^4}}}{4}} \right]_0^L}}{{\dfrac{k}{L}\left[ {\dfrac{{{x^3}}}{3}} \right]_0^L}}
Cancelling kL\dfrac{k}{L} on denominator and numerator we get
XCM=[x44]0L[x33]0L{X_{CM}} = \dfrac{{\left[ {\dfrac{{{x^4}}}{4}} \right]_0^L}}{{\left[ {\dfrac{{{x^3}}}{3}} \right]_0^L}}
Now, using the limits in the above equation we get
XCM=L440L330 XCM=3L4  {X_{CM}} = \dfrac{{\dfrac{{{L^4}}}{4} - 0}}{{\dfrac{{{L^3}}}{3} - 0}} \\\ {X_{CM}} = \dfrac{{3L}}{4} \\\
So, the centre of mass for non-uniform rod is 3L4\dfrac{{3L}}{4}

Hence, the correct option is (A)

Note The point at which the whole mass of the body appears to be concentrated is called the centre of mass of a body. In other words, the point where all the masses of the system of particles appear to be concentrated is called the centre of mass of the system of particles. Motion of this point is the same to the motion of a single particle whose mass is equal to addition of individual particles of the system and all the forces exerted on all the particles of the system by bodies which are surrounding it.
Internal force of a system can be defined as the force of mutual interaction between particles of the system.