Question
Question: What is the centre of mass of a non-uniform rod of length \[L\] which has mass per unit length \(\la...
What is the centre of mass of a non-uniform rod of length L which has mass per unit length λ=Lkx2 where k is a constant and x is the distance from the one end?
(A) 43L
(B) 8L
(C) Lk
(D) L3k
Solution
Hint As given that λ=Lkx2
∴dm=Lkx2dx
To find the centre of mass of non-uniform rod of length L so, we will use the formula-
XCM=0∫Ldm0∫Lxdm⋯(1)
where, XCM is the centre of mass of object
L is the length of object
Complete step-by-step answer:
According to the question, it is given that the length of rod is L so, we will take the limit for integration in the equation (1) we get
XCM=0∫Ldm0∫Lxdm
Now, putting the value of dm in the above equation
XCM=0∫LLkx2dx0∫LxLkx2dx
Integrating both sides with respect to x, we get
XCM=Lk[3x3]0LLk[4x4]0L
Cancelling Lk on denominator and numerator we get
XCM=[3x3]0L[4x4]0L
Now, using the limits in the above equation we get
XCM=3L3−04L4−0 XCM=43L
So, the centre of mass for non-uniform rod is 43L
Hence, the correct option is (A)
Note The point at which the whole mass of the body appears to be concentrated is called the centre of mass of a body. In other words, the point where all the masses of the system of particles appear to be concentrated is called the centre of mass of the system of particles. Motion of this point is the same to the motion of a single particle whose mass is equal to addition of individual particles of the system and all the forces exerted on all the particles of the system by bodies which are surrounding it.
Internal force of a system can be defined as the force of mutual interaction between particles of the system.