Question
Question: What is the boiling point for a \[0.743m\] aqueous solution of \[KCl\] ?...
What is the boiling point for a 0.743m aqueous solution of KCl ?
Solution
The temperature at which a liquid's vapour pressure equals the pressure surrounding the liquid, and the liquid turns into a vapour is known as the boiling point of a material. The surrounding air pressure has an effect on a liquid's boiling point.
Complete answer:
We are using the formula,
ΔTb=Tb−Tb∗=iKbm
Where,
ΔTb is the change in boiling point in ∘C from the pure solvent Tb∗ to the solution Tb .
i is the Van't Hoff factor, or an effective number of solute particles in solution. The Van't Hoff factor is ratio of the observed colligative property to the calculated colligative property.
Kb=0.512∘C/m is the boiling point constant of the water.
m is the molality of the solution.
Here we are assuming 100% dissociation of KCl .
The chemical reaction equation of KCl is given as:
KCl(aq)→K+(aq)+Cl−(aq)
We can find that the effective number of solute particles i≈1+1 .
Therefore,
Tb−Tb∗=iKbm
That is, Tb=Tb∗+iKbm
After substituting the values, we got
Tb=100∘C+2×0.512∘C/m×0.743m
Tb=100.761∘C
Hence, the boiling point of the aqueous solution is 100.761∘C .
Additional Information:
Remember the formula, ΔTb=Tb−Tb∗=iKbm . Keep in mind that when another compound is applied to a liquid, that is, a solvent, the boiling point of the liquid increases, implying that a solution has a higher boiling point than a pure solvent.
Note:
The Van 't Hoff factor, i is a measurement of a solute's effect on colligative properties like osmotic pressure, relative vapour pressure reduction, boiling-point elevation, and freezing-point depression. The ratio between the real concentration of particles formed when a substance is dissolved, and the concentration of a substance measured from its mass is known as the Van 't Hoff factor.