Question

What is the atomic mass of $NaOH$?

Answer 1

We have to know that the atomic mass is the mass of a particle. Albeit the SI unit of mass is kilogram the nuclear mass is frequently communicated in the non-SI unit Dalton where 1 Dalton is characterized as $\dfrac{1}{{12}}$ of the mass of a solitary carbon-$12$ particle, at rest. The number of protons and the number of neutrons of the core represent virtually the entirety of the absolute mass of iotas, with the electrons and atomic restricting energy making minor commitments. Accordingly, the numeric worth of the nuclear mass when communicated in Daltons has almost a similar worth as the mass number.

Complete answer:
The molar mass of $NaOH$ is $39.997g/mol$.
Clarification:
For every component of the compound, duplicate its addendum times its molar mass, then, at that point, add the outcome to get the molar mass of the compound. The molar mass of a component is its nuclear weight (mean relative nuclear mass) on the occasional table in g/mol.
The atomic mass of sodium is $22.9898{\text{ }}g/mol$.
The atomic mass of oxygen is $15.999{\text{ }}g/mol.$
The atomic mass of Hydrogen is $1.00794{\text{ }}g/mol$.
On adding every one of the molar masses of what makes sodium hydroxide.
$22.989g/mol + 15.999g/mol + 1.008g/mol = 39.996g/mol$.

Note:
We need to know that $NaOH$, otherwise called lye and scathing soda, is an inorganic compound with the equation $NaOH$ . It's anything but a white strong ionic compound composed of sodium cations. What’s more, hydroxide anions OH−. Sodium hydroxide is a profoundly harsh base and salt that decays proteins at normal encompassing temperatures and may cause serious synthetic consumption. Sodium hydroxide is profoundly solvent in water, and promptly retains dampness and carbon dioxide from the air. It's anything but a progression of hydrates $NaOH.{H_2}O$. The monohydrate $NaOH\cdot{H_2}O$ solidifies from water arrangements somewhere in the range of $12.3$ and $61.8^\circ C$ . The monetarily accessible "sodium hydroxide" is frequently this monohydrate, and distributed information may allude to it rather than the anhydrous compound.