Question
Question: What is the area of the triangle shown in the figure? 
∠C=30∘
Using Sine rule,
aSinA=cSinC
Keeping value of c = 6
a21=121
Solving it for a,
a=62
The area of the triangle is given by 2acSinB
Keeping value in this from above we get,
262×6×sin105∘
sin105∘ can also be written as
sin105∘=sin75∘=sin(30+45)=sin30∘cos45∘+sin45∘cos30∘
Used the formula of sin(A+B)
Sin105∘=221+223
So I will solve it further. We get,
221+3
Keeping it in area formula,
Thus the area is 42362×(1+3) =9+93
Hence, the area of the triangle is 9+93. So, the correct option is option (B).
Note : The area of a triangle is a measurement of the area covered by the triangle. The area of a triangle is determined by two formulas i.e. the base multiplies by the height of a triangle divided by 2 and second is Heron’s formula. Heron's formula is a method for calculating the area of a triangle when the lengths of all three sides of the triangle are given. These angles are formed by two sides of the triangle, which meets at a common point, known as the vertex. The sum of all three interior angles is equal to 180 degrees.