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Question: What is the area of the triangle shown in the figure? ![](https://www.vedantu.com/question-sets/6...

What is the area of the triangle shown in the figure?

A. 18318\sqrt 3
B. 9+939 + 9\sqrt 3
C. 9+1839 + 18\sqrt 3
D. 18+18318 + 18\sqrt 3

Explanation

Solution

Hint : Area is the quantity that expresses the extent of a two-dimensional shape. Let C\angle C as x. The sum of all the angles of the triangle is equal to 180 degrees. Using sinθ\sin \theta to find the area of the triangle. The area of a triangle is a measurement of the area covered by the triangle.

Complete step-by-step answer :
As we know, the sum of all angles inside the triangle will be equal to 180.
In the triangle ABC,
A+B+C=180\angle A + \angle B + \angle C = {180^ \circ }
As given in triangle,
A=45\angle A = {45^ \circ }
B=105\angle B = {105^ \circ }
And C=x\angle C = x
Calculate the value of x:
So,
C=180(105+45)\angle C = 180 - (105 + 45)
C=30\angle C = {30^ \circ }
Using Sine rule,
SinAa=SinCc\dfrac{{\operatorname{Sin} A}}{a} = \dfrac{{\operatorname{Sin} C}}{c}
Keeping value of c = 6
1a2=112\dfrac{1}{{a\sqrt 2 }} = \dfrac{1}{{12}}
Solving it for a,
a=62a = 6\sqrt 2
The area of the triangle is given by acSinB2\dfrac{{ac\operatorname{Sin} B}}{2}
Keeping value in this from above we get,
62×6×sin1052\dfrac{{6\sqrt 2 \times 6 \times \sin {{105}^ \circ }}}{2}
sin105\sin {105^ \circ } can also be written as
sin105=sin75=sin(30+45)=sin30cos45+sin45cos30\sin {105^ \circ } = \sin {75^ \circ } = \sin (30 + 45) = \sin {30^ \circ }\cos {45^ \circ } + \sin {45^ \circ }\cos {30^ \circ }
Used the formula of sin(A+B)\sin (A + B)
Sin105=122+322\operatorname{Sin} {105^ \circ } = \dfrac{1}{{2\sqrt 2 }} + \dfrac{{\sqrt 3 }}{{2\sqrt 2 }}
So I will solve it further. We get,
1+322\dfrac{{1 + \sqrt 3 }}{{2\sqrt 2 }}
Keeping it in area formula,
Thus the area is 362×(1+3)42\dfrac{{36\sqrt 2 \times (1 + \sqrt 3 )}}{{4\sqrt 2 }} =9+93= 9 + 9\sqrt 3
Hence, the area of the triangle is 9+939 + 9\sqrt 3. So, the correct option is option (B).

Note : The area of a triangle is a measurement of the area covered by the triangle. The area of a triangle is determined by two formulas i.e. the base multiplies by the height of a triangle divided by 2 and second is Heron’s formula. Heron's formula is a method for calculating the area of a triangle when the lengths of all three sides of the triangle are given. These angles are formed by two sides of the triangle, which meets at a common point, known as the vertex. The sum of all three interior angles is equal to 180 degrees.