Question

What is the area of the plates of a 3F parallel plate capacitor, if the separation between the plates is 5 mm ?

• A. $1.694\times10^9m^2$
• B. $4.529\times10^9m^2$
• C. $9.281\times10^9m^2$
• D. $12.981\times10^9m^2$

Answer 1

Answer: (A)

$1.694\times10^9m^2$

Answer 2

The expression of parallel plate capacitor is given by $C =\frac{ A \epsilon_{0}}{ d }$ so area of plate, $A=\frac{C d}{\epsilon_{0}}=\frac{3 \times\left(5 \times 10^{-3}\right)}{8.85 \times 10^{-12}}$ $=1.694 \times 10^{9} m ^{2}$