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Question: What is the antiderivative of \(\dfrac{2}{x}\)?...

What is the antiderivative of 2x\dfrac{2}{x}?

Explanation

Solution

An antiderivative is a function that does the opposite of the derivative. Many antiderivatives exist for a single function, but they all take the form of a function plus an arbitrary constant which is usually represented as C.
The most general antiderivative off(x)f(x) is F(x)+CF(x) + C where F(x)=f(x)F(x) = f'(x).

Complete step by step solution:
Here the antiderivative has to be found for the function 2x\dfrac{2}{x}. The antiderivative of the function is given by the expression2xdx\int {\dfrac{2}{x}} dx.
To find an antiderivative for a function f, we can often reverse the process of differentiation, add a constant and use the rules for integrals .
The above expression can be written as 2×1xdx\int {2 \times \dfrac{1}{x}} dx.
It is known to us that, 1xdx\int {\dfrac{1}{x}} dx= lnx+C\ln |x| + C.
A rule for integrals, states that cxdx=cxdx\int {cxdx = c\int {xdx} } .
Applying the rule for integrals the expression given to us which is 2xdx\int {\dfrac{2}{x}} dx becomes,
2×1xdx=21xdx\int {2 \times \dfrac{1}{x}} dx = 2\int {\dfrac{1}{x}} dx
Applying the antiderivative of 1x\dfrac{1}{x}we get,
21xdx2\int {\dfrac{1}{x}} dx =2×(lnx+C) = 2 \times (\ln |x| + C)
=2lnx+2C= 2\ln |x| + 2C
=2lnx+C1= 2\ln |x| + {C_1}(Here C1=2C{C_1} = 2C, which is another constant).
Thus, the Anti derivative of 2x\dfrac{2}{x} is 2lnx+C12\ln |x| + {C_1}.

Note:

An integral generally has a fixed limit, while an antiderivative is more general and will almost always have a +C + C, the integration constant, at the end. This is the only distinction between the two; otherwise, they are identical.
A mathematical object that can be viewed as an area or a generalisation of an area is called an integral.
The need for integration is critical. Calculating the Centre of Mass, Centre of Gravity, and Mass Moment of Inertia of a Sports Utility Vehicle, for example. To calculate an object's velocity and orbit, estimate planet positions, and comprehend electromagnetism, integration is used.