Solveeit Logo

Question

Question: What is the amount of \({{\text{H}}_2}{\text{S}}{{\text{O}}_4}\) (in grams) present in \(0.2{\text{m...

What is the amount of H2SO4{{\text{H}}_2}{\text{S}}{{\text{O}}_4} (in grams) present in 0.2moles0.2{\text{moles}} of sulfuric acid?

Explanation

Solution

A mole is simply a unit of measurement. One mole of a molecule has 6.02×10236.02 \times {10^{23}} atoms. This particular number is called Avogadro number. Relative atomic mass of an element in the periodic table is the mass of one mole of that atom. In the case of molecules, composition is given by its molecular formula.

Complete step by step answer:
Concentration is the amount of solute dissolved in a given amount of solution. There are different types of concentration units. Formula and molecular mass deal with individual atoms and molecules. Mole is the unit that relates the number of particles and mass.
It is given that the number of moles of H2SO4{{\text{H}}_2}{\text{S}}{{\text{O}}_4}, n=0.2mol{\text{n}} = 0.2{\text{mol}}
H2SO4{{\text{H}}_2}{\text{S}}{{\text{O}}_4} contains two hydrogen, one sulfur and four oxygen atoms. Thus molar mass of H2SO4{{\text{H}}_2}{\text{S}}{{\text{O}}_4} is equal to the sum of atomic masses of these three atoms.
Atomic mass of hydrogen, mH=1u{{\text{m}}_{\text{H}}} = 1{\text{u}}
Atomic mass of sulfur, mS=32.065u{{\text{m}}_{\text{S}}} = 32.065{\text{u}}
Atomic mass of oxygen, mO=16u{{\text{m}}_{\text{O}}} = 16{\text{u}}
From the above values, we can calculate the molar mass or molecular mass.
Molecular mass of H2SO4{{\text{H}}_2}{\text{S}}{{\text{O}}_4}, MH2SO4=2×1u+1×32.065u+4×16u{{\text{M}}_{{{\text{H}}_2}{\text{S}}{{\text{O}}_4}}} = 2 \times 1{\text{u}} + 1 \times 32.065{\text{u}} + 4 \times 16{\text{u}}
Simplifying, we get
MH2SO4=2+32.065+64=98.065gmol1{{\text{M}}_{{{\text{H}}_2}{\text{S}}{{\text{O}}_4}}} = 2 + 32.065 + 64 = 98.065{\text{gmo}}{{\text{l}}^{ - 1}}
Number of moles, n{\text{n}} can be calculated by dividing mass, w{\text{w}} by molar mass, M{\text{M}}.
i.e. n=wM{\text{n}} = \dfrac{{\text{w}}}{{\text{M}}}
Substituting the values of n{\text{n}} and M{\text{M}}, we get
0.2mol=w98.065gmol10.2{\text{mol}} = \dfrac{{\text{w}}}{{98.065{\text{gmo}}{{\text{l}}^{ - 1}}}}
Thus the amount of sulfuric acid in grams, w=0.2mol×98.065gmol1=19.613g{\text{w}} = 0.2{\text{mol}} \times 98.065{\text{gmo}}{{\text{l}}^{ - 1}} = 19.613{\text{g}}.
Hence the amount of H2SO4{{\text{H}}_2}{\text{S}}{{\text{O}}_4} in grams present in 0.2moles0.2{\text{moles}} of sulfuric acid is 19.613g19.613{\text{g}}.

Additional information:
Molar mass is the collective name for atomic mass and molecular mass. We use moles to calculate the number of particles, molecules, concentrations, etc. It represents a very large quantity of items.

Note:
Moles relate the mass of a single atom in amu{\text{amu}} to the mass in grams. Moles to atoms or molecules conversions can be done by multiplying with Avogadro number. Atoms or molecules to moles conversions can be done by dividing by Avogadro number. Moles to grams conversion is moles times molar mass.