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Question

Physics Question on deccay rate

What is the age of an ancient wooden piece if it is known that the specific activity of C14C^{14} nuclide in its amounts is 3/53/5 of that in freshly grown trees? Given the half of CC nuclide is 5570yr5570\, yr.

A

1000yr1000\,yr

B

2000yr2000\,yr

C

3000yr3000\,yr

D

4000yr4000\,yr

Answer

4000yr4000\,yr

Explanation

Solution

N0=35N0eλtN_{0}=\frac{3}{5}\,N_{0}e^{-\lambda t}
eλt=53e\lambda^{t}=\frac{5}{3}
logeλt=loge53\therefore log\,e^{\lambda t}=log_{e} \frac{5}{3} or λt=loge53\lambda t=log_{e} \frac{5}{3}
or t=1λloge53t=\frac{1}{\lambda}\,log_{e} \frac{5}{3}
=T0.693×0.5(T=0.693λ)=\frac{T}{0.693}\times0.5\,\left(\because T=\frac{0.693}{\lambda}\right)
=5570×0.50.693yr=\frac{5570\times0.5}{0.693}yr
=4018.7yrs=4018.7\,yrs
=4000yr= 4000\,yr