Question

What is the actual volume occupied by water molecules present in $20 \, cm^3$ of water ?

• A. $20 \, cm^3$
• B. $10 \, cm^3$
• C. $40 \, cm^3$
• D. $24.89 \, cm^3$

Answer 1

Answer: (D)

$24.89 \, cm^3$

Answer 2

Density of water $=1 g / cc$

Therefore $20 cm ^{3}$ weights 20 g of water molecules.

So number of moles of water $=\frac{20}{18}=1.11$ moles

1 mole occupies $22.4 L$.

Therefore $1.11$ moles occupies $24.89 L$, i.e., $24.89 dm ^{3}$.