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Question: What is the \({{30}^{th}}\) term of the following sequence \(2,8,14,20?\)...

What is the 30th{{30}^{th}} term of the following sequence 2,8,14,20?2,8,14,20?

Explanation

Solution

To solve this question we need to know the concept of Arithmetic Progression. A series is said to be in A.P when the common difference between all the two terms are the same. We find the value of common difference by subtracting the two consecutive terms in the series. To find the nth{{n}^{th}} term in a A.P series, the formula we use is, Tn=a+(n1)d{{T}_{n}}=a+\left( n-1 \right)d.

Complete step by step answer:
To solve this question we need to know about the behaviour of the sequence, as per the question we need to find the 30th30^{th} term. As we can see that the sequence starts from 22, so we need to find the term 30th{{30}^{th}}. The above given sequence is in Arithmetic Progression, AP as the common difference of the term is 66. Common difference is found as (n+1)th(n)th{{\left( n+1 \right)}^{th}}-{{\left( n \right)}^{th}} . We may check by subtracting 3rd{{3}^{rd}} from 4th{{4}^{th}} which is:
4th3rd\Rightarrow {{4}^{th}}-{{3}^{rd}}
2014\Rightarrow 20-14
6\Rightarrow 6
Similarly we will find the difference by subtracting 1st{{1}^{st}} term from 2nd{{2}^{nd}}
2nd1st\Rightarrow {{2}^{nd}}-{{1}^{st}}
82\Rightarrow 8-2
6\Rightarrow 6
Since the difference between the consecutive terms is 66, so the common difference is 11.
We can find the nth{{n}^{th}} term of a sequence by using the formula a+(n1)da+\left( n-1 \right)d , here a''a'' is the first term, n''n'' is the number of terms and d''d'' is the common difference of the AP. The values of these terms given in the question area=2,n=30,d=6a=2,n=30,d=6. Substituting these values in the same formula, we get:
Tn=a+(n1)d\Rightarrow {{T}_{n}}=a+\left( n-1 \right)d
T30=2+(301)×6\Rightarrow {{T}_{30}}=2+\left( 30-1 \right)\times 6
Now using BODMAS to calculate the above expression we get:
T30=2+(29)×6\Rightarrow {{T}_{30}}=2+\left( 29 \right)\times 6
T30=2+174\Rightarrow {{T}_{30}}=2+174
T30=176\Rightarrow {{T}_{30}}=176

\therefore The 30th{{30}^{th}} term of the sequence natural numbers is 2,8,14,202,8,14,20 is 176176.

Note: When numbers are in a certain series or sequence finding a particular term becomes easier. So the first step for the calculation of these types of the series, try finding the relation between each term. If we are able to find a certain relation between the terms in the series formula can directly be applied in that situation.